3 NO 鈫?N 2O + NO 2 is found to obey the rate law: rate = k[NO] 2 1st half life = 8.05 what is the 4th?

The reaction 3 NO 鈫? N 2O + NO 2 is found to obey the rate law:



rate = k[NO] 2



If the first half-life of the reaction is found to be 8.05 s, what is the length of the fourth half-life in s?3 NO 鈫?N 2O + NO 2 is found to obey the rate law: rate = k[NO] 2 1st half life = 8.05 what is the 4th?
As it is a second order reaction (Rate = k[NO]^2) then the half-life will depend upon the initial concentration of nitrogen monoxide. (Only first order reactions have a half-life that is independent of the initial concentration)..



So you need the initial concentration of NO -, then you can use the value given to calculate k and then use that to find out what you are asked..3 NO 鈫?N 2O + NO 2 is found to obey the rate law: rate = k[NO] 2 1st half life = 8.05 what is the 4th?
8.05 s.

mike geary

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